πŸ“ Step-by-Step Derivation of the Quadratic Formula πŸ”—

If you’ve studied algebra, you have likely memorized the quadratic formula. But where does it come from?

The quadratic formula isn’t just magic; it is the result of solving the standard quadratic equation for xx using a technique called completing the square.

Here is the step-by-step derivation, explaining exactly how we get from the standard form to the famous formula.

πŸ“‘ Table of Contents πŸ”—


1️⃣ Step 1: Start with the Standard Form πŸ”—

Every quadratic equation can be written in the standard form, where aa, bb, and cc are known constants, and a≠0a \neq 0:

ax2+bx+c=0ax^2 + bx + c = 0

2️⃣ Step 2: Divide by a πŸ”—

To use the “completing the square” method easily, we want the coefficient of our x2x^2 term to be 11. We achieve this by dividing the entire equation (both sides) by aa:

x2+bax+ca=0x^2 + \frac{b}{a}x + \frac{c}{a} = 0

3️⃣ Step 3: Move the Constant Term πŸ”—

Next, we isolate the terms with xx on the left side. We do this by subtracting the constant term, c/ac/a, from both sides of the equation:

x2+bax=βˆ’cax^2 + \frac{b}{a}x = -\frac{c}{a}

4️⃣ Step 4: Complete the Square πŸ”—

This is the most crucial step. We want to turn the left side of the equation into a “perfect square trinomial”β€”an expression that can be factored into the shape (x+k)2(x + k)^2.

To do this, we take exactly half of the xx coefficient (which is b/ab/a), square it, and add it to both sides to keep the equation balanced.

Half of b/ab/a is b/(2a)b/(2a). Squaring that gives us (b2a)2\left(\frac{b}{2a}\right)^2. Let’s add it to both sides:

x2+bax+(b2a)2=βˆ’ca+(b2a)2x^2 + \frac{b}{a}x + \left(\frac{b}{2a}\right)^2 = -\frac{c}{a} + \left(\frac{b}{2a}\right)^2

5️⃣ Step 5: Factor the Left Side & Square the Right Side πŸ”—

Because of how we constructed it in Step 4, the left side can now be factored perfectly into squared binomial form. On the right side, we will simply apply the square to our fraction:

(x+b2a)2=βˆ’ca+b24a2\left(x + \frac{b}{2a}\right)^2 = -\frac{c}{a} + \frac{b^2}{4a^2}

6️⃣ Step 6: Find a Common Denominator πŸ”—

To combine the fractions on the right side of the equation, we need a common denominator. The lowest common denominator for aa and 4a24a^2 is 4a24a^2.

We multiply the numerator and denominator of βˆ’c/a-c/a by 4a4a:

(x+b2a)2=βˆ’4ac4a2+b24a2\left(x + \frac{b}{2a}\right)^2 = -\frac{4ac}{4a^2} + \frac{b^2}{4a^2}

Now we can combine them into a single fraction. We’ll also rearrange the numerator to look a bit more familiar:

(x+b2a)2=b2βˆ’4ac4a2\left(x + \frac{b}{2a}\right)^2 = \frac{b^2 - 4ac}{4a^2}

7️⃣ Step 7: Take the Square Root πŸ”—

To solve for xx, we need to get rid of the square on the left side. We do this by taking the square root of both sides.

Crucial rule: When you take the square root of both sides of an equation, you must account for both the positive and negative roots (Β±\pm) on the right side.

x+b2a=Β±b2βˆ’4ac4a2x + \frac{b}{2a} = \pm\sqrt{\frac{b^2 - 4ac}{4a^2}}

We can simplify the denominator since the square root of 4a24a^2 is simply 2a2a:

x+b2a=Β±b2βˆ’4ac2ax + \frac{b}{2a} = \frac{\pm\sqrt{b^2 - 4ac}}{2a}

8️⃣ Step 8: Isolate x πŸ”—

The final step is to get xx completely by itself. We subtract b/(2a)b/(2a) from both sides:

x=βˆ’b2aΒ±b2βˆ’4ac2ax = -\frac{b}{2a} \pm \frac{\sqrt{b^2 - 4ac}}{2a}

Because both fractions already share the same denominator (2a2a), we can combine them into one final, unified expression:

x=βˆ’bΒ±b2βˆ’4ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

🎯 Conclusion πŸ”—

And there it is! By systematically completing the square, we have derived the Quadratic Formula. This formula will now allow you to solve for xx in any quadratic equation simply by plugging in the values of aa, bb, and cc.


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Updated on 2026 Oct 11.

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